0x4E4F@infosec.pub to Programmer Humor@programming.devEnglish · 14 days agoNot my problem sortinfosec.pubimagemessage-square68fedilinkarrow-up1673arrow-down112
arrow-up1661arrow-down1imageNot my problem sortinfosec.pub0x4E4F@infosec.pub to Programmer Humor@programming.devEnglish · 14 days agomessage-square68fedilink
minus-squarexmunk@sh.itjust.workslinkfedilinkarrow-up74·14 days agoGuaranteed to sort the list in nearly instantaneous time and with absolutely no downsides that are capable of objecting.
minus-squarefrezik@midwest.sociallinkfedilinkarrow-up39·14 days agoYou still have to check that it’s sorted, which is O(n). We’ll also assume that destroying the universe takes constant time.
minus-squareBatmanAoD@programming.devlinkfedilinkarrow-up42·14 days agoIn the universe where the list is sorted, it doesn’t actually matter how long the destruction takes!
minus-squaregroet@feddit.orglinkfedilinkEnglisharrow-up13·14 days agoIt actually takes a few trillion years but its fine because we just stop considering the “failed” universes because they will be gone soon™ anyway.
minus-squareBenjaben@lemmy.worldlinkfedilinkarrow-up9·14 days ago We’ll also assume that destroying the universe takes constant time. Well yeah just delete the pointer to it!
minus-squarevithigar@lemmy.calinkfedilinkarrow-up12·14 days agoExcept you missed a bug in the “check if it’s sorted” code and it ends up destroying every universe.
minus-squaredb2@lemmy.worldlinkfedilinkarrow-up6·14 days agoThere’s a bug in it now, that’s why we’re still here.
Guaranteed to sort the list in nearly instantaneous time and with absolutely no downsides that are capable of objecting.
You still have to check that it’s sorted, which is O(n).
We’ll also assume that destroying the universe takes constant time.
In the universe where the list is sorted, it doesn’t actually matter how long the destruction takes!
It actually takes a few trillion years but its fine because we just stop considering the “failed” universes because they will be gone soon™ anyway.
Eh, trillion is a constant
amortized O(0)
Well yeah just delete the pointer to it!
universe.take()Except you missed a bug in the “check if it’s sorted” code and it ends up destroying every universe.
There’s a bug in it now, that’s why we’re still here.